The molecular orbital configuration of a diatomic molecule is - 1 s2- 1 s2- 2 s2- 2 s2- 2 s2- 2 px2- - 2 py2- - 2 pz2 - Its bond order isA- 3B- 2-5C- 2D- 1

The correct option is A 3Bond Order = No. of Bonding electrons No. of antibonding electrons/2 ...

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Standard XII

Chemistry

Chemical Properties of Noble Gases

The molecular...

Question

The molecular orbital configuration of a diatomic molecule is $σ 1 s^{2} σ^{+} 1 s^{2} σ 2 s^{2} σ^{+} 2 s^{2} σ^{+} 2 s^{2} σ 2 p_{x}^{2}$ ${\begin{matrix} π 2 p_{y}^{2} π 2 p_{z}^{2} \end{matrix}$ Its bond order is

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Solution

The correct option is A 3
$B o n d O r d e r = \frac{N o . o f B o n d i n g e l e c t r o n s - N o . o f a n t i b o n d i n g e l e c t r o n s}{2}$

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The molecular orbital configuration of a diatomic molecule is σ1s2σ+1s2σ2s2σ+2s2σ+2s2σ2p2x {π2p2yπ2p2z Its bond order is

The correct option is A 3Bond Order=No. of Bonding electrons−No. of antibonding electrons2

The molecular orbital configuration of a diatomic molecule is $σ 1 s^{2} σ^{+} 1 s^{2} σ 2 s^{2} σ^{+} 2 s^{2} σ^{+} 2 s^{2} σ 2 p_{x}^{2}$ ${\begin{matrix} π 2 p_{y}^{2} π 2 p_{z}^{2} \end{matrix}$ Its bond order is

The correct option is A 3
$B o n d O r d e r = \frac{N o . o f B o n d i n g e l e c t r o n s - N o . o f a n t i b o n d i n g e l e c t r o n s}{2}$