Question

The molecular shape and hybridization state of central atom in the molecule (A) are:

• A. linear, $sp$
• B. triangular, $s{p}^2$
• C. linear, $s{p}^{3}d$
• D. V-shape, $s{p}^3$

Answer 1

The correct option is C linear, $s{p}^{3}d$

$\underset{\text{(A)}}{Xe{F}_2}+H_2\to \underset{\text{(monoatomic colorles gas (C))}}{Xe}+\underset{\text{(highly associated liquid (B) used for etching glass)}}{2HF}$
$\underset{\text{(A)}}{2Xe{F}_2}+2H_{2}O\stackrel{hydrolysis}{\to }\underset{\text{(C)}}{2Xe}+\underset{\text{(B)}}{2H_2{F}_2}+\underset{\text{diatomic gas (A)}}{O_2}$
The ionization energy of $O_2$ is similar to the ionization energy of $Xe$
$HF+KF\to \underset{\text{(Addition compound (E))}}{KH{F}_2}$
$\underset{\text{(E)}}{KH{F}_2}\underset{moltenstate}{\overset{electrolysis}{\to }}\underset{\text{reactive gas(F)}}{F_2}$
$\underset{\text{(F)}}{F_2}+\underset{\text{(C)}}{Xe}(1:1)\to \underset{\text{(A)}}{Xe{F}_2}$
Thus the compound (A) is $Xe{F}_2$ with linear shape and $s{p}^{3}d$ hybridization.