Question

The molecular shape of $S{F}_4$, $C{F}_4$ and $Xe{F}_4$ are:

• A. the same with 2, 0 and 1 lone pair of electron on the central atom respectively.
• B. the same with 1, 1 and 1 lone pair of electron on the central atom respectively.
• C. the different with 0, 1 and 2 lone pair of electron on the central atom respectively.
• D. the different with 1, 0 and 2 lone pair of electron on the central atom respectively.

Answer 1

The correct option is D the different with 1, 0 and 2 lone pair of electron on the central atom respectively.

$S{F}_4$ has a hybridisation of $s{p}^{3}d$ and molecular see- saw geometry and trigonal bipyramidal shape. The central atom contains one lone pair of electron.

$C{F}_4$ has a hybridisation of $s{p}^3$ with no lone pair of electron on central atom, so it has a tetrahedral geometry.

$Xe{F}_4$ has a hybridisation of $s{p}^3{d}^2$ has 2 loone pair of electron on the central atom.The lone pair lie in the octahedral arrangement and $Xe{F}_4$ has a square planar geometry.