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Boiling Point of Carboxylic Acids

The molecular...

Question

The molecular size of $I C l$ and $B r_{2}$ is approximately the same, but $b . p .$ if $I C l$ is about $40^{o} C$ higher that that of $B r_{2}$ It is because :

A

I C l

bond is stronger than

B r - B r

bond

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B

I E

of iodine

< I E

of bromine

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C

I C l

is polar while

B r_{2}

is nonpolar

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D

I

has larger size than

B r

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Solution

The correct options are
A $I C l$ bond is stronger than $B r - B r$ bond
C $I C l$ is polar while $B r_{2}$ is nonpolar

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Similar questions

Q. Identify the correct reason for higher boiling point of

I C l

B r_{2}

.

Polarity of a bond depends on the difference in the electronegativity of the bonded atoms. The higher the difference in the electronegativity, the higher will be the polarity of the bond.

The boiling point of

I C l

40^{\circ} C

B r_{2}

. This might be because :

Q. Both molecular solids of iodine,

I_{2}

B r_{2}

take on a similar appearance.
Which of the following explains why iodine has a higher melting point than bromine?

Q. The bond dissociation energies for

{C l}_{2}, I_{2}

I C l

242.3, 151

211.3

k J / m o l

respectively. The enthalpy of sublimation of iodine is

62.8 k J / m o l

. What is the standard enthalpy of formation of

I C l (g)

?

25.4

g of iodine and

14.2

g of chlorine are made to react completely to yield a mixture of

I C l

{I C l}_{3}

. Calculate the ratio of moles of

I C l

{I C l}_{3}

.

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Boiling Point of Carboxylic Acids

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