The molecular velocities of two gases at same temperature are $u_{1}$ and $u_{2}$ , their molar masses are $m_{1}$ and $m_{2}$ respectively. Which of the following expression is correct?

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Solution

The correct option is D

If molecular velocities are root mean square type at temperature $T$ then

$u_{1} = \sqrt{\frac{3 R T}{m_{1}}}$

$u_{2} = \sqrt{\frac{3 R T}{m_{2}}}$

$\frac{u_{1}^{2}}{u_{2}^{2}} = \frac{m_{1}}{m_{2}}$

$m_{1} u_{1}^{2} = m_{2} u_{2}^{2}$

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The molecular velocities of two gases at same temperature are u1 and u2, their molar masses are m1 and m2 respectively. Which of the following expression is correct?

The correct option is D If molecular velocities are root mean square type at temperature T then u1 = √3RTm1 u2 = √3RTm2 u21u22 = m1m2 m1u21 = m2u22

The molecular velocities of two gases at same temperature are $u_{1}$ and $u_{2}$ , their molar masses are $m_{1}$ and $m_{2}$ respectively. Which of the following expression is correct?

The correct option is D

If molecular velocities are root mean square type at temperature $T$ then

$u_{1} = \sqrt{\frac{3 R T}{m_{1}}}$

$u_{2} = \sqrt{\frac{3 R T}{m_{2}}}$

$\frac{u_{1}^{2}}{u_{2}^{2}} = \frac{m_{1}}{m_{2}}$

$m_{1} u_{1}^{2} = m_{2} u_{2}^{2}$