CameraIcon

SearchIcon

MyQuestionIcon

84

You visited us 84 times! Enjoying our articles? Unlock Full Access!

Ideal Gas Equation

The molecular...

Question

The molecular weight of 2.6 gm of a gas which occupies 2.24 litres at $0^{o} C$ & 760 mm pressure is :

A

2.6 gm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

26 gm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C

22.4 gm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

2.24 gm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 26 gm
As we know, one mole of a gaseous substance occupies 22.4 litre so
molar mass of gas $= 2.6 \times \frac{22.4}{2.24} = 26 g m$

Suggest Corrections

thumbs-up

0

Similar questions

22.4

litres of a gas weighs

70

g at S.T.P. Calculate the weight (gm) of the gas if it occupies a volume of

20

27^{o}

700

mm Hg of pressure.

Q. 16 gm of oxygen and 3 gm of hydrogen are mixed and kept in 760 mm pressure at

0^{o} C

. The total volume occupied by the mixture will be nearly:

Q. The total weight of a gas mixture which contains

11.2

C O_{2}

5.6

O_{2}

22.4

N_{2}

44.8

H e

0^{o} C

760

m m

H g

Q. The volume occupied by

3.5

O_{2}

27^{o} C

760

mm pressure is:

[Molecular weight of oxygen

= 16

Q. Volume of oxygen gas at NTP necessary for complete combustion of 20 litre of propane, measured at

0^{o} C

and 760 mm pressure is:

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

The Equation of State

PHYSICS

Watch in App

explore_more_icon

Explore more

Ideal Gas Equation

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon