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Ideal Gas Equation

The molecular...

Question

The molecular weight of a gas is $40$ . At $400$ K if $120$ g of this gas has a volume of $20$ litres, the pressure of the gas in atm is:

A

4.92

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B

5.02

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C

49.6

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D

0.546

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Solution

The correct option is B $4.92$
$P V = \frac{m}{M} R T \Rightarrow P = \frac{m}{M V} R T = \frac{120}{(40) (20)} (0.0821) (400) = (60) (0.0821) = 4.926 a t m$

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