Question

The molecular weights of two ideal gases $A$ and $B$ are respectively $100$ and $200$. One gram of $A$ occupies $V$ litre of volume at STP. What is the volume (in litre) occupied by one gram of $B$ at STP?

• A. $\frac{V}{2}$
• B. $V$
• C. $V^2$
• D. $2V$

Answer 1

The correct option is A $\frac{V}{2}$

Under identical conditions of temperature and pressure:
$\frac{V_A}{V_B}=\frac{n_A}{n_B}$
$\frac{V_A}{V_B}=\frac{1/100}{1/200}$
$V_B=\frac{V}{2}$.