Question

The molecule/ion in which bond angle is les than ${109}^{\circ }$?

• A. $N{F}_4^{+}$
• B. $CC{l}_4$
• C. $CL{O}_4{}^{-}$
• D. None of these

Answer 1

Answer: (D)

None of these

(a) In nitrogen tetrafluoride molecule, the hydridization of $N$ atom is $s{p}^3$.
Since, all the substitutents are same, the bond $\angle FNF={109.5}^{\circ }$
(b) In carbon tetrachlorid molecule, hydridization of $C$ atom is $s{p}^3$
All the four substituents are same. Hence, $\angle ClCCl={109.5}^{\circ }$
(c) In $Cl{O}_4^{-}$ molecule, the hybridization of $Cl$ atpm is $s{p}^3$. Since, all the substituents are same, the bond $\angle OCIO:{109.5}^{\circ }$
All the four carbon oxygen bonds have equal length.