Question

The molecules having the same hybridization and number of lone pairs of electrons is:

• A. $Se{F}_4,Xe{O}_2{F}_2$
• B. $S{F}_4,Xe{F}_2$
• C. $XeO{F}_4,Te{F}_4$
• D. $SeC{l}_4,Xe{F}_4$

Answer 1

The correct option is A $Se{F}_4,Xe{O}_2{F}_2$

(a) $Se{F}_4$ and $Xe{O}_2{F}_2$ are both $s{p}^{3}d$ hybridised and see-saw shaped with one lone pair of electron each.
(b) $S{F}_4$ has one lone pair and $Xe{F}_2$ has 3 lone pairs.
(c) $XeO{F}_4$ is $s{p}^3{d}^2$ with one lone pair.
$Te{F}_4$ is $s{p}^{3}d$ with one lone pair.
(d) $SeC{l}_4$ is $s{p}^{3}d$ with one lone pair.
$Xe{F}_4$ is $s{p}^3{d}^2$ with 2 lone pairs.