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Byju's Answer

Standard XII

Chemistry

Graham's Law of Effusion

The molecules...

Question

The molecules of a gas A travel four times faster than the molecules of gas B at the same temperature. The ratio of molecular weights $\frac{M_{A}}{M_{B}}$ will be

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Solution

The correct option is A

$\frac{r_{A}}{r_{B}} = 4 = \sqrt{\frac{M_{B}}{M_{A}}}$
$\Rightarrow \frac{M_{B}}{M_{A}} = 16$
$∴ \frac{M_{A}}{M_{B}} = \frac{1}{16}$

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The molecules of a gas A travel four times faster than the molecules of gas B at the same temperature. The ratio of molecular weights MAMB will be

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$\frac{r_{A}}{r_{B}} = 4 = \sqrt{\frac{M_{B}}{M_{A}}}$
$\Rightarrow \frac{M_{B}}{M_{A}} = 16$
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