The molecules of a given mass of gas have a root mean square velocity of 200m-s-1 at 270C and 1-0-105N-m-2 pressure- When the temperature is 1270C and the pressure 0-5- 105 Nm-2- the root mean square velocity is ms-1- is

The correct option is A 400/√(3) C_2/C_1 =√( 400/300) = 2/√(3) #160; ⇒ C_2 = 2/√(3)×200 = 400/√(3)ms^ 1 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Ideal Gas Equation

The molecules...

Question

The molecules of a given mass of gas have a root mean square velocity of $200 m . s^{- 1}$ at $27^{0} C$ and $1.0 \times 10^{5} N . m^{- 2}$ pressure. When the temperature is $127^{0} C$ and the pressure $0.5 \times 10^{5} N m^{- 2}$ , the root mean square velocity is $m s^{- 1}$ , is

\frac{400}{\sqrt{3}}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

100 \sqrt{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{100 \sqrt{2}}{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{100}{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $\frac{400}{\sqrt{3}}$
$\frac{C_{2}}{C_{1}}$ $= \sqrt{\frac{400}{300}}$
$= \frac{2}{\sqrt{3}}$ $\Rightarrow$ $C_{2}$
$= \frac{2}{\sqrt{3}} \times 200$
$= \frac{400}{\sqrt{3}} m s^{- 1}$

Suggest Corrections

Similar questions

Q. The molecules of a given mass of a gas have r.m.s velocity of

200 {m s}^{- 1}

27^{0} C

and

1.0 \times 10^{5} N m^{- 2}

pressure. When the temperature and pressure of the gas are respectively,

127^{0} C

and

0.05 \times 10^{5} N m^{- 2}

, the r.m.s. velocity of its molecules in

{m s}^{- 1}

is:

Q. The molecules of a given mass of a gas have root mean square speeds of

100

s^{- 1}

27

^{o} C

and

1

atmospheric pressure. The root mean square speeds of the molecules of the gas at

127

^{o} C

and

2

atmospheric pressure is?

Q. The density of air at pressure of

10^{5} N m^{- 2}

1.2 k g m^{- 3}

. Under these conditions the root mean square velocity of the air molecules is

m s^{- 1}

Q. The rms velocity of gas molecules of a given amount of a gas at

27^{\circ} C

and

1.0 \times 10^{5} {N m}^{- 2}

pressure is

200 {m sec}^{- 1}

. If temperature and pressure are respectively

127^{\circ} C

and

0.5 \times 10^{5} {N m}^{- 2}

, the rms velocity will be:

The molecules of a given mass of a gas have root mean square speed of $100 m s^{- 1}$ at $27^{\circ} C$ and 1 atmospheric pressure. What will be the root mean square speeds of the molecules of the gas at $127^{\circ} C$ and 2 atmospheric pressure?

Join BYJU'S Learning Program

The molecules of a given mass of gas have a root mean square velocity of 200m.s−1 at 270C and 1.0×105N.m−2 pressure. When the temperature is 1270C and the pressure 0.5×105Nm−2, the root mean square velocity is ms−1, is

The correct option is A 400√3 C2C1 =√ 400300= 2√3 ⇒ C2= 2√3×200= 400√3ms−1

The molecules of a given mass of gas have a root mean square velocity of $200 m . s^{- 1}$ at $27^{0} C$ and $1.0 \times 10^{5} N . m^{- 2}$ pressure. When the temperature is $127^{0} C$ and the pressure $0.5 \times 10^{5} N m^{- 2}$ , the root mean square velocity is $m s^{- 1}$ , is

The correct option is A $\frac{400}{\sqrt{3}}$
$\frac{C_{2}}{C_{1}}$ $= \sqrt{\frac{400}{300}}$
$= \frac{2}{\sqrt{3}}$ $\Rightarrow$ $C_{2}$
$= \frac{2}{\sqrt{3}} \times 200$
$= \frac{400}{\sqrt{3}} m s^{- 1}$