Question

The moment of a force of 5N about a point is 2 Nm. Calculate the distance of the point from the point of application of force.

• A. 0.1 m
• B. 2.5 m
• C. 10 m
• D. 0.4 m

Answer 1

The correct option is D. 0.4 m.

Given,

Force = $F=5N$

Moment of force (or torque ) = $\tau =2Nm$

Let the distance of point of application of force from point P be $r$.

We know that,

$\tau =r_{\perp }F$

$⟹20=r_{\perp }\times 5$

$⟹r_{\perp }=\frac{20}{5}$

$⟹r_{\perp }=4m$

Thus the distance of the point from the point of application of force is 4 m.