The torque due to a force of $10 N$ acting tangentially about a point P is $5 N m$ . Calculate the distance of the point of application of the force from the point P.

20 cm

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40 cm

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50 cm

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60 cm

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Solution

The correct option is C
50 cm

Given, moment of force = $5 N m$ , Force $F$ = $10 N$
We know that,
Moment of force = $r \times F$
$r = \frac{M o m e n t o f f o r c e}{F} = \frac{5}{10} = 0.5 m = 50 c m$

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The torque due to a force of 10 N acting tangentially about a point P is 5 N m. Calculate the distance of the point of application of the force from the point P.

The correct option is C 50 cm Given, moment of force = 5 N m, Force F = 10 N We know that, Moment of force = r×F r = Moment of forceF = 510 = 0.5 m = 50 cm

The torque due to a force of $10 N$ acting tangentially about a point P is $5 N m$ . Calculate the distance of the point of application of the force from the point P.

The correct option is C
50 cm

Given, moment of force = $5 N m$ , Force $F$ = $10 N$
We know that,
Moment of force = $r \times F$
$r = \frac{M o m e n t o f f o r c e}{F} = \frac{5}{10} = 0.5 m = 50 c m$