The moment of inertia of a body about a given axis is 1.2kg×m2. Initially, the body is at rest. In order to produce a rotational KE of 1500 joule, an angular acceleration of 25rads2 must be applied about that axis for a duration of
A
4 seconds
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2 seconds
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
8 seconds
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
10 seconds
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B 2 seconds KR=12Iω2=12I(αt)2=12Iα2t2 ⇒1500=12×1.2×(25)2t2 ⇒t2=4⇒t=2seconds
Hence, the correct answer is option (b).