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Question

The moment of inertia of a meter stick of mass 400g about an axis passing through 20cm mark and perpendicular to its length is

A
3.9×105cm2
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B
2.9×105cm2
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C
4.9×105cm2
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D
6.9×105cm2
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Solution

The correct option is B 6.9×105cm2

Moment of inertia of metre stick about its centre is given by:

I=ML212

I=0.4×1212

Now moment of inertia about axis perpendicular to length of stick at 20 cm mark

I=0.13+0.4×(310)2

I=0.13+3.6100

I=10+10.8300

I=20.8300

I=0.069kgm2

I=6.9×105gcm2


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