The moment of inertia of a regular circular disc of mass $0.4 k g$ and radius $100 c m$ about an axis. perpendicular to the plane of the disc and passing through its centre is

0.2 k g m^{2}

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0.02 k g m^{2}

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0.002 k g m^{2}

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2 k g m^{2}

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Solution

The correct option is B $0.2 k g m^{2}$
Moment of inertia of a circular disc
$= \frac{1}{2} M R^{2} = \frac{1}{2} \times 0.4 \times 1 \times 1 = 0.2 k g m^{2}$

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The moment of inertia of a regular circular disc of mass 0.4 kg and radius 100 cm about an axis. perpendicular to the plane of the disc and passing through its centre is

The correct option is B 0.2 kg m2Moment of inertia of a circular disc=12MR2=12×0.4×1×1=0.2kgm2

The moment of inertia of a regular circular disc of mass $0.4 k g$ and radius $100 c m$ about an axis. perpendicular to the plane of the disc and passing through its centre is

The correct option is B $0.2 k g m^{2}$
Moment of inertia of a circular disc
$= \frac{1}{2} M R^{2} = \frac{1}{2} \times 0.4 \times 1 \times 1 = 0.2 k g m^{2}$