Question

The moment of inertia of a sphere about an axis passing through its centre is 2/5MR2. Find its radius of gyration by stating suitable law along a tangent

Answer 1

Dear Student,


$$\begin{gathered} I=\frac{2M{R}^2}{5} \\ lettheradiusofgyrationbex \\ I=M{x}^2 \\ \frac{2M{R}^2}{5}=M{x}^2 \\ x=\sqrt{\frac{2}{5}}R \\ Regards \end{gathered}$$