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Question

The moment of inertia of a thin square plate ABCD of uniform thickness about an axis passing through the centre O and perpendicular to the plane of the plate is :

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A
I1+I2
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B
I3+I4
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C
I1+I3
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D
I1+I2+I3+I4
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Solution

The correct options are
A I1+I2
B I3+I4
According to perpendicular axis theorem, if Ix,Iy and Iz be moments of inertia about axis x, y and z respectively, the perpendicular axis theorem states that Ix+Iy=Iz
Here
Iz be moment of inertia about an axis passing through the center O and perpendicular to the plane of the plate.
So, when Ix=I1,Iy=I2, then Iz=I1+I2
When
Ix=I3,Iy=I4, then Iz=I3+I4
So we get I1=I2=I3=I4
Thus we get the required answers.
141711_72920_ans.png

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