1
Question
The moment of inertia of a thin uniform rod of mass 4 kg and length I metre about an axis ⊥ r to its length is 0.43kgm2. Calculate the distance of this axis from nearer end of the rod.
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Solution
Length of the rod = 1
m, mass of the rod = 0.5 kg
Let at a distance d
from the center the rod is moving Applying parallel axis theorem :
The moment of inertial
about that point
(mL2 / 12)
+ md2 = 0.10
(0.5 × 12)/12 + 0.5 ×
d2 = 0.10
d2 = 0.2 –
0.082 = 0.118
d = 0.342 m from the
centre.
Length of the rod = 1 m, mass of the rod = 0.5 kg
Let at a distance d from the center the rod is moving Applying parallel axis theorem :
The moment of inertial about that point
(mL2 / 12) + md2 = 0.10
(0.5 × 12)/12 + 0.5 × d2 = 0.10
d2 = 0.2 – 0.082 = 0.118
d = 0.342 m from the centre.
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