The moment of inertia of HCl molecule about an axis passing through its centre of mass and perpendicular to the line joining the $H^{+}$ and $C l^{-}$ ions will be, if the interatomic distance is 1 $o A$

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Solution

The correct option is B
If $r_{1}$ and $r_{2}$ are the respective distances of particles $m_{1}$ and $m_{2}$ from the centre of mass then
$m_{1} r_{1} = m_{2} r_{2} \Rightarrow 1 \times x = 35.5 \times (L - x) \Rightarrow x = 35.5 (1 - x)$
$\Rightarrow x = 0.973 o A$ and $L - x = 0.027 o A$
Moment of inertia of the system about centre of mass $I = m_{x}^{2} + m_{2} (L - x)^{2}$
$I = 1 a m u \times (0.973 o A)^{2} + 35.5 a m u \times (0.027 o A)^{2}$
Substituting 1 a.m.u. $= 1.67 \times 10^{- 27} k g$ and $1 o A = 10^{- 10} m$
$I = 1.62 \times 10^{- 47} k g m^{2}$

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The moment of inertia of HCl molecule about an axis passing through its centre of mass and perpendicular to the line joining the H+ and Cl− ions will be, if the interatomic distance is 1 oA

The moment of inertia of HCl molecule about an axis passing through its centre of mass and perpendicular to the line joining the $H^{+}$ and $C l^{-}$ ions will be, if the interatomic distance is 1 $o A$