The moment of inertia of the body about an axis is $1.2 k g - m^{2}$ . Initially the body is at rest. In order to produce a rotational kinetic energy of $1500 J$ , an angular acceleration of $25 r a d / s^{2}$ must be applied about the axis for the duration of

2 s

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4 s

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8 s

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10 s

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Solution

The correct option is A $2 s$
$\begin{matrix} K i n e t i c E n e r g y = 1500 J S o, \frac{1}{2} ∣ ∣ π^{2} = 1500 J ∣ ∣ = 1.2 S o, π^{2} = 2500 s o, π = 50 B y π = α x t 50 = 25 t s o, t = 2 sec . \end{matrix}$

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Similar questions

Q. The moment of inertia of a body about a given axis is

1.2 kg - m^{2}

. Initially, the body is at rest. In order to produce a rotational kinetic energy of

1500 J

, an angular acceleration of

25 {rad/s}^{2}

must be applied about that axis for a duration of

The moment of inertia of a body about a given axis is $1.2 k g m^{2}$ . Initially the body is at rest. In order to produce a rotational kinetic energy of 1500J, an angular acceleration of $25 r a d / s e c^{2}$ must be applied about that axis for a duration of: