The momentum of a body of mass 0.5kg is 20 kg m/s. The kinetic energy of this body will be

400 J

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40 J

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200 J

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20 J

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Solution

The correct option is A 400 J
$P = 20 k g m s^{- 1}; m = 0.5 k g$
$P = m v$
$20 = 0.5 v; v = 40 m s^{- 1}; v^{2} = 1600 m s^{- 1}$
K.E $= \frac{1}{2} m v^{2} = \frac{1}{2} \times 0.5 \times 1600 = 400 J$

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