The momentum of a body of mass 200 g having a kinetic energy of 10 J is

2000 kg.m/s

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20 kg.m/s

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2 kg.m/s

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0.2 kg.m/s

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Solution

The correct option is C 2 kg.m/s
Mass, m $= 200 g m = 0.2 k g$
$K . E = 10 J$
$M o m e n t u m, P = ?$
As, $\frac{1}{2} m v^{2} = 10$
$v^{2} = \frac{10 \times 2}{0.2} = 100$
$v = 10 m s^{- 1}$
Momentum, P $= m v = 0.2 \times 10 = 2 k g m / s$
Hence, option C is correct.

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