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Question

The momentum of a particle having a de-Broglie wavelength of 0.1 ˚A is (approximately),

A
6.63×1023 kg m sec1
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B
6.63×1022 kg m sec1
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C
6.63×1020 kg m sec1
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D
6.63×1024 kg m sec1
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Solution

The correct option is A 6.63×1023 kg m sec1
The de-Broglie wavelength is given by,
λ=hp
p=hλ
p=6.63×10341011=6.63×1023 kg m sec1

Hence, (A) is the correct answer.
Key concept: Particle travelling with certain velocity behaves as both wave and particle and de-Broglie wavelength formula can be used to calculate the same.

Why this question?Simple application of de-Broglie equation.

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