Dear student,
let mess m, and velocity v
kinetic energy =( 1/2)mv2
And momentum = mv
kinetic energy(E) related by momentum(p) by
E = p2/(2m)
Now if momentum is doubled,
Initial momentum is p1=p and finally p2= 2p
So, E1= p2/(2m)
and finally
E2= (2p)2/(2m) = (4p2)/(2m) = 4E1
So if momentum doubled kinetic energy change by 4 times.
Regards