The momentum P and kinetic energy E of a body of mass m are related as :

P = \sqrt{2 m E}

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P = \frac{1}{2} m E

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P = \frac{2 m}{E}

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P = 2 m E

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Solution

The correct option is A $P = \sqrt{2 m E}$
A. $P = \sqrt{2 m E}$

lets,

$m =$ mass of a body

$v =$ velocity of body.

The kinetic energy, $E = \frac{1}{2} m v^{2}$ . . . . .. . (1)

The momentum, $P = m v$ . . . . . . . (2)

In equation (1), multiply and divide by $m$

$E = \frac{P^{2}}{2 m}$

$P^{2} = 2 m E$

$P = \sqrt{2 m E}$

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The momentum P and kinetic energy E of a body of mass m are related as :

The correct option is A P=√2mEA. P=√2mElets,m= mass of a bodyv= velocity of body.The kinetic energy, E=12mv2. . . . .. . (1)The momentum, P=mv. . . . . . . (2)In equation (1), multiply and divide by mE=P22mP2=2mEP=√2mE