The moon is about $384000 k m$ from the earth and it's path around the earth is nearly circular. Find the circumference of the path described by the moon in one complete revolution about the earth (use $π = 3.14$ )

Open in App

Solution

The circumference of a circle, $C = 2 π r$ where $r$ is the radius of the circle.
Here, $r = 384000 k m$
So circumference of the path $= 2 π r = 2 \times 3.14 \times 384000 = 24, 11, 520 k m .$
So, the circumference of the path is $24, 11, 520 k m .$

Suggest Corrections

106

Similar questions

Q. The moon is about

384000 k m

from the earth and is nearly circular. Find the circumference of the path described by the moon in one complete revolution about the earth. (use

π = 3.14

)

Question 130

The moon is about 384000 km from earth and its path around the earth is nearly circular. Find the length of the path described by moon in one complete revolution. (Take, $π = 3.14$ )

Q. The moon is about 384400 km from the earth and its path around the earth is nearly circular. Find the circumference of the path described by the moon in lunar month.

Q. Which of the following statements is true?
Statement - 1: A saree

5.5 m

long and

1.25 m

wide has a zeri border

2.5 c m

broad along its length on either side. Along the width, on one edge the border was

5 c m

wide and on the other side the zari was

25 c m

wide. The area of the zaro is

5855 c m^{2}

.
Statement - 2: The moon is about

384000 k m

from earth and its path around the earth is nearly circular. The length of path described by moon in one complete revolution will be

2, 411, 520 k m . (π = 3.14)

Find the acceleration of the moon with respect to the earth from the following data : Diistance between the earth and the moon = $3.85 \times 10^{5}$ km and the time taken by the moon to complete one revolution around the earth = 27.3 days.

Join BYJU'S Learning Program

The moon is about 384000 km from the earth and it's path around the earth is nearly circular. Find the circumference of the path described by the moon in one complete revolution about the earth (use π=3.14)

The circumference of a circle, C=2πr where r is the radius of the circle. Here, r=384000 kmSo circumference of the path =2πr=2×3.14×384000=24,11,520 km.So, the circumference of the path is 24,11,520 km.

The moon is about $384000 k m$ from the earth and it's path around the earth is nearly circular. Find the circumference of the path described by the moon in one complete revolution about the earth (use $π = 3.14$ )

The circumference of a circle, $C = 2 π r$ where $r$ is the radius of the circle.
Here, $r = 384000 k m$
So circumference of the path $= 2 π r = 2 \times 3.14 \times 384000 = 24, 11, 520 k m .$
So, the circumference of the path is $24, 11, 520 k m .$