The moon is about $384000 k m$ from the earth and it's path around the earth is nearly circular. Find the circumference of the path described by the moon in one complete revolution about the earth (use $π = 3.14$ )

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Solution

The circumference of a circle, $C = 2 π r$ where $r$ is the radius of the circle.
Here, $r = 384000 k m$
So circumference of the path $= 2 π r = 2 \times 3.14 \times 384000 = 24, 11, 520 k m .$
So, the circumference of the path is $24, 11, 520 k m .$

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The moon is about 384000 km from the earth and it's path around the earth is nearly circular. Find the circumference of the path described by the moon in one complete revolution about the earth (use π=3.14)

The circumference of a circle, C=2πr where r is the radius of the circle. Here, r=384000 kmSo circumference of the path =2πr=2×3.14×384000=24,11,520 km.So, the circumference of the path is 24,11,520 km.

The moon is about $384000 k m$ from the earth and it's path around the earth is nearly circular. Find the circumference of the path described by the moon in one complete revolution about the earth (use $π = 3.14$ )

The circumference of a circle, $C = 2 π r$ where $r$ is the radius of the circle.
Here, $r = 384000 k m$
So circumference of the path $= 2 π r = 2 \times 3.14 \times 384000 = 24, 11, 520 k m .$
So, the circumference of the path is $24, 11, 520 k m .$