Question

The moon is observed from two diametrically opposite points A and B on Earth. The angle $\theta$ substantiated at the moon by the two direction of observation is $1^o{54}^{\prime }$. Given the diameter of the Earth to be about $1.276\times$10^7m . compute the distance of the moon from the Earth.

Answer 1

Given, $d=1.276\times {10}^{7}m,\theta =1^0{54}^{\prime }={114}^{\prime }=114\times 60=114\times 60\times {10}^{-6}=3.32\times {10}^{-6}rad$

So, the distance of the moon from the Earth is $s=\frac{d}{\theta }=\frac{1.276\times {10}^7}{3.32\times {10}^{-6}}=3.84\times {10}^8$

Moreover, The Moon is observed diametrically oppositive that is moving by two direction of observation that is respective to a certain distance.