The moon's distance from the earth is $360000$ km and its diameter subtends an angle of $42^{'}$ at the eye of the observer. The diameter of the moon is?

4400

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1000

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3600

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8800

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Solution

The correct option is B $4400$ km
We know that
angle $= \frac{a r c}{r a d i u s} = \frac{a r c}{R}$
here the diameter
of moon will be
trated as are
So
angle $= \frac{α}{R}$
$\Rightarrow=$ angle $\times R = \frac{7 π}{1800} \times 36, 0000 \times 10^{3}$ meter
$\Rightarrow d = 4396 \times 10^{2}$ meer $= 4396 k m \approx 4400 k m$

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The moon's distance from the earth is 360000 km and its diameter subtends an angle of 42′ at the eye of the observer. The diameter of the moon is?

The correct option is B 4400 kmWe know thatangle =arcradius=arcRhere the diameterof moon will betrated as areSo angle =αR⇒= angle ×R=7π1800×36,0000×103 meter⇒d=4396×102 meer =4396 km≈4400 km

The moon's distance from the earth is $360000$ km and its diameter subtends an angle of $42^{'}$ at the eye of the observer. The diameter of the moon is?