Question

# The moon's radius is $$1/4$$ times that of the earth and its mass $$1/80$$ times that of the earth. If g represents the acceleration due to gravity on the surface of the earth, then on the surface of the moon its value is :

A
g/4
B
g/5
C
g/6
D
g/8

Solution

## The correct option is B $$g/5$$Acceleration due to gravity on the earth's surface is $$g=\dfrac{GM_e}{R_e^2}$$Acceleration due to gravity on the moon's surface is $$g_m=\dfrac{GM_m}{R_m^2}$$Given, $$R_m=\dfrac{R_e}{4}$$ or $$\dfrac{R_m}{R_e}=\dfrac{1}{4}$$ and $$M_m=\dfrac{M_e}{80}$$ or $$\dfrac{M_m}{M_e}=\dfrac{1}{80}$$So, $$\dfrac{g_m}{g}=\dfrac{M_m}{M_e}\times (\dfrac{R_e}{R_m})^2=(1/80)\times (4)^2=1/5$$or $$g_m=g/5$$Physics

Suggest Corrections

0

Similar questions
View More

People also searched for
View More