Question

The most common oxidation state of Lanthanoid elements is +3. Which of the following is likely to deviate easily from +3 oxidation state?

• A. Lu (At. No. 71)
• B. Gd (At. No. 64)
• C. La (At. No. 57)
• D. Ce (At. No. 58)

Answer 1

The correct option is D Ce (At. No. 58)

$Ce\to \left[Xe\right]4f^{1}5d^{1}6s^2$
$C{e}^{4+}\to \left[Xe\right]4f^{0}5d^{0}6s^0$
Cerium in +4 oxidation state acquires inert gas configuration.