Question

# The most commonly used reducing agent is:

A
AlCl3
B
PbCl2
C
SnCl4
D
SnCl2

Solution

## The correct option is C $$SnCl_2$$+4 oxidation state of $$Sn$$ is more stable than +2 oxidation state. Therefore, $${Sn}^{2+}$$ can be easily oxidised to $${Sn}^{4+}$$ and hence $$Sn{Cl}_{2}$$ acts a reducing agent.$$Sn{Cl}_{2} + 2Cl \longrightarrow Sn{Cl}_{4} + 2{e}^{-}$$Chemistry

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