The most contributing tautomeric enol form of MeCOCH 2 CO 2 Et is-A- H 2 C - C OH CH 2 CO 2 EtB- MeC OH - CHCO 2 EtC- 2-PentanoneD- 2 -Butene

The correct option is B MeC(OH) = CHCO2Et Let's take a look at the structure: Me ||OC CH_2 O||C OEt CH_3 ||OC CH_2 O||C OEt [Here we have two α hydrogens from ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Chemistry

Nomenclature of Unsaturated Hydrocarbons

The most cont...

Question

The most contributing tautomeric enol form of $M e C O C H_{2} C O_{2} E t$ is?

H₂C=C(OH)CH₂CO₂Et

No worries! We‘ve got your back. Try BYJU‘S free classes today!

MeC(OH) = CHCO₂Et

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2-Pentanone

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2-Butene

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
MeC(OH) = CHCO₂Et

Let's take a look at the structure:

$M e - O | | C - C H_{2} - C | | O - O E t$

$C H_{3} - O | | C - C H_{2} - C | | O - O E t$ [Here we have two $α$ -hydrogens from different carbons]

But here,

Because it will form hydrogen bonding and make five membered ring.

Suggest Corrections

Similar questions

The most contributing tautomeric enol form of $M e C O C H_{2} C O_{2} E t$ is:

Q. The most contributing tautomeric enol. form of

M e C O C H_{2} C O_{2} E t

is :

Q. The most contributing tautomeric enol from of

M e C O C H_{2} C O_{2} E t

is :

Q. In keto-enol tautomerism of 1,3-dicarbonyl compounds, the enol form is preferred in contrast to the keto-enol form, this is due to:

In keto - enol tautomerism of dicarbonyl compounds, the enol form is preferred in contrast to the keto-form this is due to

Join BYJU'S Learning Program

The most contributing tautomeric enol form of MeCOCH2CO2Et is?

The correct option is B MeC(OH) = CHCO2Et Let's take a look at the structure: Me−O||C−CH2−C||O−OEt CH3−O||C−CH2−C||O−OEt [Here we have two α-hydrogens from different carbons] But here, Because it will form hydrogen bonding and make five membered ring.

The most contributing tautomeric enol form of $M e C O C H_{2} C O_{2} E t$ is?