The most contributing tautomeric enol. form of $M e C O C H_{2} C O_{2} E t$ is :

H_{2} C = C (O H) C H_{2} C O_{2} E t

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M e C (O H) = C H C O_{2} E t

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M e C O C H = C (O H) O E t

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H_{2} C = C (O H) C H = C (O H) E t

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Solution

The correct option is A $M e C (O H) = C H C O_{2} E t$
Tautomerism :- Tautomers are isomers of a compound which differ only in the position of the protons and electrons. The carbon skeleton of the compound is unchanged.

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The most contributing tautomeric enol form of $M e C O C H_{2} C O_{2} E t$ is?

The most contributing tautomeric enol form of $M e C O C H_{2} C O_{2} E t$ is:

M e C O C H_{2} C O_{2} E t

- E

$B r C H_{2} C H B r C H_{2} B r a l c . K O H - ---- \to [X] C H_{3} O^{-} - --- \to Y; [X]$ and [Y] respectively are

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