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Question

The most general value of θ which satisfies both the equations tanθ=3andcosecθ=23 is-

A
nπ+4π3:nI
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B
nπ2π3:nI
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C
2nπ+4π3:nI
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D
2nπ+2π3:nI
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Solution

The correct option is D 2nπ+4π3:nI
tanθ=3
tanθ=tanπ3
θ=π3,4π3,..............
cosecθ=23
θ=4π3 [θ=4π3satisfy the negative value of cosecθ=23]
θ=2nπ+4π3
When n=1
θ=2π+4π3
θ=3π+π3
tan(3π+π3)=3
cosec(3π+π3)=23
For θ=2nπ+4π3 satisfies for values of tanθ and cosecθ.

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