wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The most general values of θ, satisfying the two equations, cosθ=12,tanθ=1 is

A
2nπ±5π4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2nπ+π4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
nπ+5π4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(2n+1)π+π4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D (2n+1)π+π4
cosθ=12 or tanθ=1
θ=2nπ±3π4 or θ=π4
θ=(2n+1)π+π4

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Solving Trigonometric Equations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon