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Byju's Answer
Standard XII
Mathematics
Solving Simultaneous Trigonometric Equations
The most gene...
Question
The most general values of
θ
, satisfying the two equations,
c
o
s
θ
=
−
1
√
2
,
t
a
n
θ
=
1
is
A
2
n
π
±
5
π
4
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B
2
n
π
+
π
4
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C
n
π
+
5
π
4
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D
(
2
n
+
1
)
π
+
π
4
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Solution
The correct option is
D
(
2
n
+
1
)
π
+
π
4
cos
θ
=
−
1
√
2
or
tan
θ
=
1
⇒
θ
=
2
n
π
±
3
π
4
or
θ
=
π
4
∴
θ
=
(
2
n
+
1
)
π
+
π
4
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0
Similar questions
Q.
The general solution of
(
√
3
−
1
)
sin
θ
+
(
√
3
+
1
)
cos
θ
=
2
is
(where
n
∈
Z
)
Q.
The values of
x
which satisfying both the equations
cos
x
=
−
1
√
2
and
tan
x
=
1
simultaneously is :
Q.
Assertion :The value of
θ
,
0
<
θ
<
π
2
,
satisfying the equation
6
∑
m
=
1
c
o
s
e
c
[
θ
+
(
m
−
1
)
π
4
]
c
o
s
e
c
[
θ
+
m
π
4
]
=
4
√
2
are
π
12
and
5
π
12
Reason: If
tan
θ
+
cot
θ
=
4
,
0
<
θ
<
π
2
,
then
θ
=
π
12
or
5
π
12
.
Q.
General solution of the equation
sec
2
x
=
−
2
√
3
is
Q.
If
cos
x
=
|
sin
x
|
, then the general solution is
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