The most ionic and most covalent compounds respectively from the following are:
$C r O_{5}, M n_{2} O_{7}, P b O, P_{4} O_{10}, S n O_{2}$

C r O_{5}, M n_{2} O_{7}

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P b O, M n_{2} O_{7}

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C r O_{5}, P_{4} O_{10}

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S n O_{2}, C r O_{5}

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Solution

The correct option is B $P b O, M n_{2} O_{7}$
As anion is same, the covalent character in ionic compound will depend upon the size and charge on the cation. According to Fajan's rule, PbO is most ionic because Pb $^{2 +}$ has less polarising power where as Mn $_{2}$ O $_{7}$ is most covalent because Mn $^{7 +}$ has higher polarising power.
Hence, the most ionic compound is $P b O$ and most covalent is $M n_{2} O_{7}$ .

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C r O_{5}, M n_{2} O_{7}, P b O, S n O_{2}

C r O_{5}, M n_{2} O_{7}, P b O, S n O_{2}

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C r O_{5} + H_{2} S O_{4} \to C r_{2} (S O_{4})_{3} + H_{2} O + O_{2},

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