The most ionic halide of $M g$ will be :

M g I_{2}

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M g B r_{2}

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M g F_{2}

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M g C l_{2}

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Solution

The correct option is C $M g F_{2}$
Because of the highest electronegativity difference between $M g$ and $F$ , $M g F_{2}$ is the most ionic halide among the four.

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