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The most nega...

Question

The most negative oxidation state of an atom of group 15 (VA) element is equal to the number of electrons required to fill the valence shell of the neutral atom. If true enter 1,if false enter 0.

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Solution

Outer shell electronic configuration : Ns $^{2}$ np $4^{3}$
(Three electrons less than octet)
Number of electrons required to fill the valence shell $=$ 3
Hence, $X^{3 -}$ has configuration $= n s^{2} n p^{6}$
$X^{3 -}$ has stable nearest inert gas configuration hence most negative oxidation state $=$ -3.

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