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Standard X

Chemistry

Electrochemical Series

The most powe...

Question

The most powerful oxidising agent of the following is

I_{2}

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F_{2}

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B r_{2}

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C l_{2}

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Solution

The correct option is C $F_{2}$
The bond dissociation energy of fluorine is lowest and heat of hydration is highest among halogens. These two factors make the fluorine the most powerful oxidising agent, through its electron affinity is lower than $C l$ .

Hence, option B is correct.

Suggest Corrections

Similar questions

Q. Increasing oxidising nature of

I_{2}, {B r}_{2}, {C l}_{2}, F_{2}

is :

I_{2} < {B r}_{2} < {C l}_{2} < F_{2}

.
if true enter 1, else enter 0.

Q. Consider the following orders –
(1)

F_{2} > C l_{2} > B r_{2} > I_{2} :

boiling point
(2)

F_{2} > C l_{2} > B r_{2} > I_{2} :

oxidizing nature
(3)

F_{2} > C l_{2} > B r_{2} > I_{2} :

EN
(4)

F_{2} > C l_{2} > B r_{2} > I_{2} :

BDE
(5)

F_{2} > C l_{2} > B r_{2} > I_{2} :

EA
(6)

F_{2} > C l_{2} > B r_{2} > I_{2} :

Reactivity
(7)

H O C l > H C l O_{2} > H C l O_{3} > H C l O_{4} :

Acidic nature
(8)

H O C l > H C l O_{2} > H C l O_{3} > H C l O_{4} :

Oxidizing nature
Then calculate

(x^{2} + y^{2})

when

x

is correct order and

y

is incorrect order.

The correct order of the oxidizing power of Cl₂, Br₂, I₂ and O₂ is:

Q. Assertion :

{C l}_{2}

{B r}_{2}

changes

K I

into

I_{2}

(violet in

{C C l}_{4}

layer),

{C l}_{2}

changes

K B r

into

{B r}_{2}

(orange-yellow in

{C C l}_{4}

layer). Thus,

{C l}_{2}

would change mixture of

K I a n d K B r

into violet layer in

{C C l}_{4}

. Reason: Oxidising power is in order

I_{2} < {B r}_{2} < {C l}_{2} < F_{2}

Q. Write the Bond Energy order of :

F_{2}, C l_{2}, B r_{2}, I_{2}

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The most powerful oxidising agent of the following is

The correct option is C F2The bond dissociation energy of fluorine is lowest and heat of hydration is highest among halogens. These two factors make the fluorine the most powerful oxidising agent, through its electron affinity is lower than Cl.Hence, option B is correct.

The correct option is C $F_{2}$
The bond dissociation energy of fluorine is lowest and heat of hydration is highest among halogens. These two factors make the fluorine the most powerful oxidising agent, through its electron affinity is lower than $C l$ .

Hence, option B is correct.