The most probable radius in pm for finding the electron in He -isA- 0-0B- 52-9C- 26-5D- 105-8

The correct option is C 26.5 Most probable radius = a_0/Z Where a_0 = 52.9 pm. For helium ion, Z=2. r_mp = 52.9/2 = 26.45 pm. ...

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The most probable radius (in pm) for finding the electron in $H e^{+}$ is

0.0

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52.9

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26.5

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105.8

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H e^{+}

[P (r)]

\frac{d P (r)}{d r}

Z

\frac{d P}{d r} = \frac{4 Z^{3}}{a_{0}^{3}} (2 r - \frac{2 Z r^{2}}{a_{0}}) e^{\frac{- 2 Z r}{a_{0}}}

\frac{d P (r)}{d r}

\frac{d P}{d r} = \frac{4 Z^{3}}{a_{0}^{3}} (2 r - \frac{2 Z r^{2}}{a_{0}}) e^{- 2 Z r / a_{0}}

18 p m

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