The most probable speed of $8 g$ of $H_{2} is 200 {ms}^{- 1}$ . The average kinetic energy (neglect rotational and vibrational energy) of $H_{2}$ gas is:

480 J

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240 J

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120 J

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None of these

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Solution

The correct option is B $240 J$
The value of most probable speed is $\sqrt{\frac{2 R T}{M}}$ , when speed is in $m s^{- 1}$ and molar mass $(M)$ of gas is taken in Kg/mol.
According to the question:
$200 = \sqrt{\frac{2 R T}{2 \times 10^{- 3}}}$
$\Rightarrow R T = 40$
Average Kinetic energy (K.E.) for one mol of gas particles $= \frac{3}{2} n R T = \frac{3}{2} \times \frac{8}{2} \times 40$
$= 240 J$

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The most probable speed of 8 g of H2 is 200 ms−1. The average kinetic energy (neglect rotational and vibrational energy) of H2 gas is:

The correct option is B 240 JThe value of most probable speed is √2RTM, when speed is in ms−1 and molar mass (M) of gas is taken in Kg/mol. According to the question: 200=√2RT2×10−3 ⇒RT=40 Average Kinetic energy (K.E.) for one mol of gas particles =32nRT=32×82×40 =240 J

The most probable speed of $8 g$ of $H_{2} is 200 {ms}^{- 1}$ . The average kinetic energy (neglect rotational and vibrational energy) of $H_{2}$ gas is: