The motion of a body is given by dvdt=6−3v where v is the velocity (in ms−1) at a time t (in seconds). The body is at rest at t = 0. The terminal speed of the body is
2 ms−1
The acceleration is given by
a=dvdt=6−3v........(i)
The terminal speed v1 is the speed when the acceleration is zero.
Using a = 0 in equation (i), 0=6−3v1
⇒v1=2 m/s
Hence, the correct option is (b).