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Byju's Answer
Standard XII
Physics
Time Period Independent of Amplitude
The motion of...
Question
The motion of a mass
m
attached to a spring of spring constant
k
is shown in the figure.
The net force on the spring is
A
F
s
p
r
i
n
g
=
−
k
x
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B
F
s
p
r
i
n
g
=
−
k
x
+
m
g
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C
F
s
p
r
i
n
g
=
k
x
−
m
g
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D
F
s
p
r
i
n
g
=
k
x
+
m
g
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Solution
The correct option is
A
F
s
p
r
i
n
g
=
−
k
x
F
s
p
r
i
n
g
=
m
(
a
−
g
)
The only force acting on the spring is tension force wich is equalt to
−
k
x
wich in turn is equal to
m
(
a
−
g
)
Suggest Corrections
0
Similar questions
Q.
Two equal masses are attached to the two ends of a spring of spring constant k. The masses are pulled out symmetrically to stretch the spring by a length x over its natural length. The work done by the spring on each mass is
(a)
1
2
k
x
2
(b)
-
1
2
k
x
2
(c)
1
4
k
x
2
(d)
-
1
4
k
x
2