The motion of a particle along a straight line is described by equation x=8+12t−t3 where, x is in metre and t in sec. The retardation of the particle when its velocity becomes zero is :
A
24ms−2
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B
zero
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C
6ms−2
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D
12ms−2
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Solution
The correct option is B12ms−2
x=8+12t−t3V=dxdt=12−3t2
∴V=0 at t=±2s, negative time has no significance,
∴t=2s
a=dVdt=−6t∴a at t=2=−6×2=−12m/s2
Thus, retardation when velocity becomes 0 is 12ms−2