The motion of a particle along a straight line is described by equation x=8+12tt3 where x is in metre and t in second. The retardation of the particle when its velocity becomes zero is
A
6 ms−2
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B
12 ms−2
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C
24 ms−2
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D
Zero
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Solution
The correct option is B12 ms−2 x=8+12t−t3 v=dxdt=12−3t2 a=dvdt=−6t putting v=0 3t2=12 t=2sec a=−6×2=−12ms−2 Retardation =12ms−2