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Question

The motion of a particle along a straight line is described by the function x=(2t−3)2 where x is in meters and t is in seconds. Find the velocity of the particle at the origin.

A
0 m/s
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B
1 m/s
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C
2 m/s
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D
3 m/s
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Solution

The correct option is A 0 m/s
Position of the particle is given by
x=(2t3)2
Time at which the particle is at origin will be given by
0=(2t3)2
t=32
Velocity of the particle at any instant will be
v=dxdt=2(2t3)×2=4(2t3)
At t=32 i.e. when the particle is at origin, v=0

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