The motion of a particle along a straight line is described by the function x=(2t−3)2 where x is in meters and t is in seconds. Find the velocity of the particle at the origin.
A
0m/s
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B
1m/s
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C
2m/s
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D
3m/s
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Solution
The correct option is A0m/s Position of the particle is given by x=(2t−3)2
Time at which the particle is at origin will be given by 0=(2t−3)2 ⟹t=32
Velocity of the particle at any instant will be v=dxdt=2(2t−3)×2=4(2t−3)
At t=32 i.e. when the particle is at origin, v=0