The motion of a particle executing SHM is given by x = 0.01 sin 100, where x is in metre and time t is in second. The time period is

0.2s

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0.1s

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0.02s

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0.01s

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Solution

The correct option is C 0.02s
$x = 0.01 s i n 100 π (t + 0.05)$
$= 0.01 s i n (100 π t + 5 π)$
$∴$ Angular frequency $ω = 100 π = \frac{2 π}{T}$

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The motion of a particle executing SHM is given by x = 0.01 sin 100, where x is in metre and time t is in second. The time period is

The correct option is C 0.02sx=0.01sin100π(t+0.05) =0.01sin(100πt+5π) ∴ Angular frequency ω=100π=2πT

The correct option is C 0.02s
$x = 0.01 s i n 100 π (t + 0.05)$
$= 0.01 s i n (100 π t + 5 π)$
$∴$ Angular frequency $ω = 100 π = \frac{2 π}{T}$