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Standard XII

Physics

Kepler's Law

The motion of...

Question

The motion of a planet around sun in an elliptical orbit is shown in the following figure. Sun is situated on one focus. The shaded areas are equal. If the planet takes time $t_{1}$ and $t_{2}$ in moving from A to B and from C to D respectively then

t_{1} > t_{2}

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t_{1} < t_{2}

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t_{1} = t_{2}

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Solution

The correct option is B $t_{1} = t_{2}$
According to kepler's second law of equal areas,The speed of planet in its orbit varies in such a way that radius vector joining the planet to sun sweeps out equal areas in equal intervals of time. It is also states that planet sweeps equal areas in equal intervals of time.
Therfore, $t_{1}, t_{2}$ are equal.

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The motion of a planet around sun in an elliptical orbit is shown in the following figure. Sun is situated on one focus. The shaded areas are equal. If the planet takes time t1 and t2 in moving from A to B and from C to D respectively then

The motion of a planet around sun in an elliptical orbit is shown in the following figure. Sun is situated on one focus. The shaded areas are equal. If the planet takes time $t_{1}$ and $t_{2}$ in moving from A to B and from C to D respectively then